017 SQL COUNT

The webpage explains the SQL COUNT() function. Here’s a summary of the key points:

Interactive SQL examples and a short quiz are provided for hands-on learning on the page.[1]

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SQL COUNT() Function

The SQL COUNT() Function

The COUNT() function returns the number of rows that matches a specified criterion.

Find the total number of rows in the Products table:

SELECT COUNT(*)
FROM Products;

Syntax

SELECT COUNT(column_name)
FROM table_name
WHERE condition;

Demo Database

Below is a selection from the Products table used in the examples:

ProductID ProductName SupplierID CategoryID Unit Price
1 Chais 1 1 10 boxes x 20 bags 18
2 Chang 1 1 24 - 12 oz bottles 19
3 Aniseed Syrup 1 2 12 - 550 ml bottles 10
4 Chef Anton's Cajun Seasoning 2 2 48 - 6 oz jars 22
5 Chef Anton's Gumbo Mix 2 2 36 boxes 21.35

Specify Column

You can specify a column name instead of the asterix symbol (*).

If you specify a column name instead of (*), NULL values will not be counted.

Find the number of products where the ProductName is not null:

SELECT COUNT(ProductName)  
FROM Products;

Add a WHERE Clause

You can add a WHERE clause to specify conditions:

Find the number of products where Price is higher than 20:

SELECT COUNT(ProductID)  
FROM Products  
WHERE Price > 20;

Ignore Duplicates

You can ignore duplicates by using the DISTINCT keyword in the COUNT() function.

If DISTINCT is specified, rows with the same value for the specified column will be counted as one.

How many different prices are there in the Products table:

SELECT COUNT(DISTINCT Price)  
FROM Products;

Use an Alias

Give the counted column a name by using the AS keyword.

Name the column "Number of records":

SELECT COUNT(*) AS [Number of records]
FROM Products;

Use COUNT() with GROUP BY

Here we use the COUNT() function and the GROUP BY clause, to return the number of records for each category in the Products table:

SELECT COUNT(*) AS [Number of records], CategoryID  
FROM Products  
GROUP BY CategoryID;

You will learn more about the [GROUP BY](https://www.w3schools.com/sql/sql_groupby.asp) clause later in this tutorial.